Complete question.
Kindly view the omitted graph in the picture attached.
Answer: 10 + √10
Explanation:
Given that the triangle is an isosceles triangle, such that AB = AC
TO CALCULATE SEGMENT AB:
From the graph ;
A(-2,-4) and B(2,-1)
AB = sqrt[(2 - - 2)^2 + (-1 - - 4)^2
AB = sqrt[4^2 + 3^2]
AB = sqrt(16 + 9)
AB = 5
Therefore, AB = AC = 5 Units
To get segment BC:
Coordinates of B(2,-1) and C(3,-4)
BC = sqrt[(3 - 2)^2 + (-4 - - 1)^2
BC = sqrt[1^2 + -3^2]
BC = sqrt(1 + 9)
BC = √10
The perimeter is therefore,
AB + AC + BC
5 + 5 + √10
= 10 + √10
