Answer:
Initial velocity(u)=62.6 m/s^2
Time(t)=6.39 seconds
Solution,
Displacement(s)=200 m
Initial velocity (u)=?
Final velocity(v)=0 m/s^2
acceleration due to gravity(g)=-9.8 m/s^2
now,
[tex] {v}^{2} = {u}^{2} + 2as \\ {(0)}^{2} = {u}^{2} + 2 \times ( - 9.8) \times 200 \\ {u}^{2} = 2 \times 9.8 \times 200 \\ {u}^{2} = 3920 \\ u = \sqrt{3920} \\ u = \sqrt{ {62.6}^{2} } \\ u = 62.6 \: metre \: per \: second[/tex]
Again,
Finding time taken,
[tex]v = u + at \\ t = \frac{v - u}{a} \\ = \frac{0 - 62.6}{ - 9.8} \\ = \frac{ - 62.6}{ - 9.8} \\ = 6.39 \: seconds[/tex]
Hope this helps...
Good luck on your assignment...
