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(a) Design a low-pass filter with a cutoff frequency of 12 kHz. Use0.15 uF capacitor and an appropriate resistor. B) Sketch and label the circuit. C) What is the gain of the filter at a frequencyof 20 kHz? Give your answer both as ratio (Vout/Vin) and in dB

Respuesta :

batolisis

Answer:

A) 88.42 ohms

c) 0.5145 and - 5.77 db

Explanation:

A)  Value of cut-off frequency = 12 kHz

capacitance of capacitor =0.15 microF

formula for cut-off frequency of a low-pass filter

[tex]Fc = \frac{1}{2\pi RC}[/tex]   making R the subject of the formula in other to get the resistance of the low pass filter resistor

R = [tex]\frac{1}{2\pi (12*10^3)(0.15*10^{-6} )}[/tex] = 88.42 OHMS

attached is the solution for B and C

Ver imagen batolisis