Answer:
(S)-3-methoxy-3-methylbutan-2-ol
Explanation:
In this case, we have an epoxide opening in acid medium. The first step then is the protonation of the oxygen. Then the epoxide is broken to generate the most stable carbocation. The nucleophile ([tex]CH_3OH[/tex]) will attack the carbocation generating a new bond. Finally, the oxygen is deprotonated to obtain an ether functional group and we will obtain the molecule (S)-3-methoxy-3-methylbutan-2-ol.
See figure 1
I hope it helps!