Answer:
It will have a population of 61,779 in 2000.
Step-by-step explanation:
The population for the city, in t years after 1900, can be modeled by a exponential function with constant growth rate in the following format:
[tex]P(t) = P(0)(1+r)^{t}[/tex]
In which P(0) is the population in 1900 and r is the growth rate.
Population of 24,000 in 1900
This means that [tex]P(0) = 24000[/tex]
Population of 29,000 in 1920.
1920 is 1920 - 1900 = 20 years after 1900.
This means that P(20) = 29000. So
[tex]P(t) = P(0)(1+r)^{t}[/tex]
[tex]29000 = 24000(1+r)^{20}[/tex]
[tex](1+r)^{20} = \frac{29000}{24000}[/tex]
[tex]\sqrt[20]{(1+r)^{20}} = \sqrt[20]{\frac{29000}{24000}}[/tex]
[tex]1 + r = 1.0095[/tex]
So
[tex]P(t) = P(0)(1+r)^{t}[/tex]
[tex]P(t) = 24000(1.0095)^{t}[/tex]
What population will it have in 2000
2000 is 2000 - 1900 = 100 years after 1900. So this is P(100).
[tex]P(t) = 24000(1.0095)^{t}[/tex]
[tex]P(100) = 24000(1.0095)^{100} = 61779[/tex]
It will have a population of 61,779 in 2000.
