Respuesta :
Answer: The relationship between the equilibrium constant [tex](K_c)[/tex] of reaction and the rate constants for the forward [tex](k_f)[/tex] and reverse [tex](k_r)[/tex] reactions in a single step reaction is [tex]K_c=\frac{k_f}{k_b}[/tex]
Explanation:
Equilibrium constant is the ratio of product of the concentration of products to the product of concentration of reactants.
For example if the reaction is : [tex]X\rightleftharpoons Y[/tex]
[tex]K_c=\frac{[Y]}{[X]}[/tex]
Rate of forward direction=[tex]k_f[X][/tex]
Rate of backward direction=[tex]k_b[Y][/tex]
At equilibrium, Rate of forward direction = Rate of backward direction
thus [tex]\frac{k_f}{k_b}=\frac{Y}{X}[/tex]
where [tex]\frac{Y}{X}=K_c[/tex]
Thus [tex]\frac{k_f}{k_b}=K_c[/tex]
