Answer:
A= the households own mutual funds
B= the household own individual stocks
[tex]A \cap B[/tex] the household own both
And we know the following probabilities:
[tex] P(A)= 0.56, P(B)= 0.39, P(A \cap B) = 0.23[/tex]
For this case we want to find this probability:
households that own individual stocks but not mutual funds
And we can find this with:
[tex] P(B-A) =P(B) -P(B \cap B)[/tex]
And replacing we got:
[tex] P(B-A) =P(B) -P(B \cap B)=0.39-0.23= 0.16[/tex]
Step-by-step explanation:
For this problem we can define the following notation:
A= the households own mutual funds
B= the household own individual stocks
[tex]A \cap B[/tex] the household own both
And we know the following probabilities:
[tex] P(A)= 0.56, P(B)= 0.39, P(A \cap B) = 0.23[/tex]
For this case we want to find this probability:
households that own individual stocks but not mutual funds
And we can find this with:
[tex] P(B-A) =P(B) -P(B \cap B)[/tex]
And replacing we got:
[tex] P(B-A) =P(B) -P(B \cap B)=0.39-0.23= 0.16[/tex]
