Answer:
F = 3.84*10^-34N ^j
Explanation:
In order to calculate the magnetic force on the electron you use the following formula:
[tex]\vec{F}=q\vec{v} \ X\ \vec{B}[/tex] (1)
q: charge of the electron = -1.6*10^-19C
B: magnitude of the magnetic field = 0.80T
v: speed of the charge = 3.0*10^5 m/s
The direction of the motion of the electron is in the +i^ direction (+x direction). The magnetic field is in the +^k direction (+z direction).
The cross product between these unit vectors, by taking into account the minus sign of the charge, is given by:
-^i X ^k = ^j
The magnetic force is in the ^j direction (+y direction).
The magnitude of the magnetic force is:
[tex]F=qvB=(1.6*10^{-19}C)(3.0*10^5m/s)(0.80T)=3.84*10^{-34}N[/tex]
The magnetic force on the electron has a magnitude of 3.84*10^-34N in the +y direction
