Answer:
28.72 mA
Explanation:
The computation is shown below:-
The expression for the magnetic field at the center
[tex]B = \mu_0\ nI[/tex]
Where I indicate current in the solenoid
n indicates the number of turns per unit length of the solenoid
indicates permeability of free space
Now,
The expression for the number of turns per unit length
[tex]n = \frac{N}{l}[/tex]
where
n indicates the number of turns
and l indicates the length of the solenoid
now we will combine n and b to reach the value of I
[tex]B = \mu_o \frac{N}{l} I[/tex]
So,
[tex]I = \frac{Bl}{\mu_0N}[/tex]
[tex]= \frac{(1.0 \times 10^{-4}T) (0.390\ m)}{4\pi \times 10^{-7}\frac{T.m}{A} (1,080)}[/tex]
[tex]= 28.72 \times 10^-3\ A[/tex]
= 28.72 mA