contestada

long solenoid that has 1 080 turns uniformly distributed over a length of 0.390 m produces a magnetic field of magnitude 1.00 10-4 T at its center. What current is required in the windings for that to occur

Respuesta :

Answer:

28.72 mA

Explanation:

The computation is shown below:-

The expression for the magnetic field at the center  

[tex]B = \mu_0\ nI[/tex]

Where I indicate current in the solenoid  

n indicates the number of turns per unit length of the solenoid

indicates permeability of free space

Now,

The expression for the number of turns per unit length  

[tex]n = \frac{N}{l}[/tex]

where

n indicates the  number of turns  

and l indicates the length of the solenoid

now we will combine n and b to reach the value of I

[tex]B = \mu_o \frac{N}{l} I[/tex]

So,

[tex]I = \frac{Bl}{\mu_0N}[/tex]

[tex]= \frac{(1.0 \times 10^{-4}T) (0.390\ m)}{4\pi \times 10^{-7}\frac{T.m}{A} (1,080)}[/tex]

[tex]= 28.72 \times 10^-3\ A[/tex]

= 28.72 mA