Answer:
The number of people would have participate in opinion poll
n = 15,267
Step-by-step explanation:
Step(i):-
Given data an opinion poll reported that 36% believe a certain governor broke campaign financing laws in his election campaign.
Given proportion = 36% =0.36
Given the margin of error = 1% =0.01
Level of significance = 99% 0 r 0.01
Z₀.₀₁ = 2.576
step(ii):-
The margin of error of Population proportion is determined by
[tex]M.E = \frac{Z_{0.01} \sqrt{p(1-p)} }{\sqrt{n} }[/tex]
[tex]0.01 = \frac{2.576 \sqrt{0.36(1-0.36)} }{\sqrt{n} }[/tex]
[tex]\sqrt{n} = \frac{2.576 \sqrt{0.36(1-0.36)} }{0.01 }[/tex]
√n = 123.648
Squaring on both sides , we get
n = 15,267
final answer:-
The number of people would have participate in opinion poll
n = 15,267
