Answer:
(a) μ = 0.015kg/m
(b) v = 90.64m/s
Explanation:
(a) The linear density of the string is given by the following relation:
[tex]\mu=\frac{m}{L}[/tex] (1)
m: mass of the string = 25.3g = 25.3*10-3 kg
L: length of the string = 1.62m
[tex]\mu=\frac{25.3*10^{-3}kg}{1.62m}=0.015\frac{kg}{m}[/tex]
The linear density of the string is 0.015kg/m
(b) The velocity of the string for the fundamental frequency is:
[tex]f_1=\frac{v}{2l}[/tex] (2)
f1: fundamental frequency = 41.2 Hz
vs: speed of the wave
l: distance between the fixed extremes of the string = 1.10m
You solve for v in the equation (2) and replace the values of the other parameters:
[tex]v=2lf_1=2(1.10m)(41.2Hz)=90.64\frac{m}{s}[/tex]
The speed of the wave for the fundamental frequency is 90.64m/s
