Answer:
The answer is "340 units²"
Step-by-step explanation:
In the given question, an attachment file is missing, which can be defined as follows:
[tex]\therefore \tan \theta= \frac{height}{base}\\\\\to \tan 60^{\circ}=\frac{h}{3}\\\\\to \sqrt{3}=\frac{h}{3}\\\\\to 3\sqrt{3}=h\\\\\to h = 3\sqrt{3} units\\\\[/tex]
The area of trapezoid prism:
[tex](a)= (b_1+b_2)h+ph[/tex]
value:
[tex]b_1=6 \ units\\b_2=9 \units\\h=10 \ units\\\\\to P=6+9+3\sqrt{3}+\sqrt{3^2+(3\sqrt{3})^2}\\\\\to P=15+3\sqrt{3}+\sqrt{9+27}\\\\\to P=15+3\sqrt{3}+\sqrt{36}\\\\\to P=21+3\sqrt{3} \ unit\\\\\bold{ Area= (6+9) \times 3\sqrt{3}+(21+3\sqrt{3})\times 10}\\\\\to Area= (15) \times 3\sqrt{3}+(21+3\sqrt{3})\times 10\\\\\to Area= 45\sqrt{3}+210+30\sqrt{3}\\\\\to Area=339.9038\\\\\to Area=340 \ units^2[/tex]
