Answer:
9.93 m/s
Explanation:
The following data were obtained from the question:
Mass (m) = 1500 Kg
Initial velocity (u) = 5.25 m/s
Force (F) = 1250 N
Distance (s) = 42.8 m
Final velocity (v) =...?
Next, we shall determine the acceleration of car. This can be achieved as shown below:
Force (F) = mass (m) x acceleration (a)
1250 = 1500 x a
Divide both side by 1500
a = 1250/1500
a = 0.83 m/s²
Therefore, the acceleration of the car is 0.83 m/s²
Now, we can determine the final velocity of car as shown below:
Initial velocity (u) = 5.25 m/s
Distance (s) = 42.8 m
Acceleration (a) = 0.83 m/s²
Final velocity (v) =...?
v² = u² + 2as
v² = (5.25)² + 2 x 0.83 x 42.8
v² = 27.5625 + 71.048
v² = 98.6105
Take the square root of both side
v = √98.6105
v = 9.93 m/s
Therefore, the final velocity of the car is 9.93 m/s
