Answer:
[tex]9\sqrt{5}[/tex]
Step-by-step explanation:
To simplify this radical, you want to first find the prime factorization of the radicand, which happens to be 45.
The lowest square root factor of 45 is 3.
Now, the radical looks like this:
[tex]\sqrt{3^2\cdot \:5}\\=\sqrt{5}\sqrt{3^2}[/tex]
Of course, The square root of a squared number is still the same number so...
[tex]=3\sqrt{5}[/tex]
Now, we aren't done here, as the 3 which was multiplied by the square root of 45 is still existent so...
[tex]=3 \cdot 3\sqrt{5} \\=9\sqrt{5}[/tex]
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