Answer:
I do 1 option for you as an example, you need to check the leftover by yourself.
Step-by-step explanation:
for d) y(0) = 0 and y'(pi) =0
[tex]y(0) = C_1e^0cos(0)+ C_2 e^0 sin(0) = 0 \longrightarrow C_1 = 0[/tex]
[tex]y(x) ' = C_1e^x cos(x) - C_1e^x sin (x) + C_2e^x sin(x) + C_2e^x cos(x)[/tex]
[tex]y(\pi)'=C_1e^\pi cos(\pi)- C_1e^\pi sin(\pi)+ C_2e^\pi sin(\pi) + C_2e^\pi cos (\pi)[/tex]
Replace [tex]C_1 = 0[/tex] we have
[tex]y'(\pi) = -C_2e^\pi = 0[/tex]
if and only if [tex]C_2 =0[/tex]
Hence the given solution does not work.
then, d is NOT the correct answer.