Answer: P(3 boys)=1/8
P(1 boy)=3/8
P(2 boys)=3/8
P(0 boys)=1/8
Step-by-step explanation:
Lets use letter B-for the boys and letter G for the girls
Lets use for any situation description 3 simbols.
For example GBG - mens 1st kid is girl, second is boy and the third one is girl again
We have only 1 set of 3 BOYS : B-B-B -TOTAL 1 set
The sets of 2 BOYS are looking as follows: B-B-G, B-G-B, G-B-B - TOTAL 3 sets
The sets of 1 BOY are looking as follows: B-G-G, G-B-G, G-G-B - TOTAL 3 sets
Finally we have only 1 set of 0 BOYS : G-G-G -TOTAL 1 set
Total amount of sets is 8.
So probability of 3 boysamong 3 kids is P(3 BOYS)=1/8
probability of 2 boys among 3 kids is P(2 BOY)=3/8
probability of 1 boy among 3 kids is P(1 BOY)=3/8
probability of 0 boy among 3 kids is P(1 BOY)=1/8