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A 0.15 g honeybee acquires a charge of 22 pC while flying. The electric field near the surface of the earth is typically 100 N/C , directed downward. What is the ratio of the electric force on the bee to the bee's weight

Respuesta :

Answer:

[tex]1.50\ *10^{-6} }[/tex]

Explanation:

Given

e=100 N/C

M=0.15 g

[tex]q=\ 22\ pC\\=\ 22\ *10^{-2}[/tex]

The  ratio of the electric force on the bee to the bee's weight can be determined by the following formula

[tex]\frac{fe}{M*9.81}[/tex]

[tex]\frac{22*10^{-12\ *\ 100} }{0.15*\ 10^{-3} *\ 9.81}[/tex]

[tex]=\ 1.50\ *10^{-6}[/tex]

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