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Suppose a NASCAR race car rounds one end of the Martinsville Speedway. This end of the track is a turn with a radius of approximately 57.0 m . If the track is completely flat and the race car is traveling at a constant 26.5 m/s (about 59 mph ) around the turn, what is the race car's centripetal (radial) acceleration

Respuesta :

Answer:

The centripetal acceleration of the car will be 12.32 m/s² .

Explanation:

Given that

radius ,R= 57 m

Velocity , V=26.5 m/s

We know that centripetal acceleration given as follows

[tex]a_c=\dfrac{V^2}{R}[/tex]

Now by putting the values in the above equation we get

[tex]a_c=\dfrac{26.5^2}{57}=12.32\ m/s^2[/tex]

Therefore the centripetal acceleration of the car will be 12.32 m/s² .

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