Answer:
The answer is given below
Explanation:
Given that:
Compression ratio (r) = 18, cut off ratio ([tex]r_c[/tex]) = 1.5, k = 1.4, W = 150 hp, initial temperature (Ti) = 17°C = 290 K
The rate of heat addition (Qin) is given by the equation:
[tex]Q_{in}=\frac{W*r^{k-1}*k(r_c-1)}{r^{k-1}*k(r_c-1)-(r_c^k-1)} \\\\substituting\ values\ into\ the \ equation\ gives:\\\\Q_{in}=\frac{150*18^{1.4-1}*1.4(1.5-1)}{18^{1.4-1}*1.4(1.5-1)-(1.5^{1.4}-1)}=\frac{333.6555}{2.2244-0.7641} =\frac{333.6555}{1.4603} =228.5\ hp[/tex]
Therefore, The rate of heat addition is 228.5 hp
The maximum air temperature is determined using the Compression ratio, cut off ratio and the initial temperature. The maximum air temperature ([tex]T_{max}[/tex]) is given by the formula:
[tex]T_{max}=T_{in}*r^{k-1}*r_c=290*18^{1.4-1}*1.5=1382.3\ K=1109.3^oC[/tex]
The maximum air temperature is 1109.3°C