Answer:
i) 0.05 T
ii) 0.025 T
Explanation:
current I = 4 A
length of solenoid L = 100 cm = 1 m
number of turns N = 10000 turns
number of turns per unit length n = N/L = 10000/1 = 10000 turns/meter
i) magnetic field on the axis of the solenoid at the center
B = μ[tex]nI[/tex]
where μ is vacuum permeability = 4π×10−7 H/m = 1.256 x [tex]10^{-6}[/tex] H/m
B = 1.256 x [tex]10^{-6}[/tex] x 10000 x 4 = 0.05 T
ii) magnetic field on the axis at the end will be equal to
B = (μ[tex]nI[/tex]) ÷ 2
this is based on the assumption that the length of the solenoid is far greater than than the diameter of the solenoid. Therefore,
B = 0.05 ÷ 2 = 0.025 T
