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if p(x) = x2 – 1 and q(x)=5(x-1), which expression is equivalent to (p – q)(x)? a: 5(x – 1) – x2 – 1 b: (5x – 1) – (x2 – 1) c: (x2 – 1) – 5(x – 1) d: (x2 – 1) – 5x – 1

Respuesta :

nobillionaireNobley
p(x) = x^2 - 1
q(x) = 5(x - 1)
(p - q)(x) = (x^2 - 1) - 5(x - 1)

Answer:

Option c is true.

( [tex](p-q)(x)=(x^2-1)-5(x-1)[/tex] ) .

Step-by-step explanation:

We are given:

[tex]p(x) = x^2-1[/tex] and [tex]q(x)=5(x-1)[/tex].

Now we are asked to find the expression of:

[tex](p-q)(x)[/tex]

We know that the expression (p-q)(x) could also be written as:

[tex](p-q)(x)=p(x)-q(x)[/tex]

Hence, [tex](p-q)(x)=(x^2-1)-(5(x-1))\\\\(p-q)(x)=(x^2-1)-5(x-1)[/tex]

Hence option c is true i.e. the expression is:

[tex](p-q)(x)=(x^2-1)-5(x-1)[/tex]

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