Answer:
Mo:780
Bo:120
Step-by-step explanation:
We are given that
Mo:my number has two periods .One period has a 7 in the hundred place , other has an 8 in the tens place and other digits are zero.
Then the number of Mo's=[tex]7\times 100+8\times 10+0=780[/tex]
Bo: My number has two periods,one has a 1 in the hundred place ,other has a 2 in the tens place and other digits are zero.
Therefore, number of Bo's =[tex]1\times 100+2\times 10+0=120[/tex]
Hundred place of Mo's number is greater than the hundred place of Bo's number , therefore,Mo's number is greater than the Bo's number.