Answer:
The answer to this question can be described as follows:
Step-by-step explanation:
Given equation:
[tex]\bold{0.5x-7= \sqrt{(-5x+29)}}[/tex]
As in the given question the two ways to solve the equation can be defined as follows:
First way:
Let square the above-given equation then we will get:
[tex]\to (0.5x-7)^2= (\sqrt{(-5x+29)})^2\\\\\to (0.5x)^2 +7^2-2\times 0.5x\times 7= -5x+29\\\\\to 0.25x^2 +49- 7x= -5x+29\\\\\to 0.25x^2 - 7x+5x +49-29=0\\\\\to 0.25x^2 - 2x+20=0\\\\[/tex]
The calculated equation doesn't have any like term that's why it can't be factorised.
Second way:
after calculating the equation that is [tex]0.25x^2-2x+20=0[/tex], it graph is given in attachment please find.
