Answer:
Dr Khan will add 5 liters of 20% acetic acid solution.
Step-by-step explanation:
Dr Khan is combining two solutions of acetic acid with the given concentrations of 20% and 60% respectively.
Let the amount of 20% acetic acid, he added to get 10 liters of 40% solution = 'a' liters
Volume of 60% solution used will be = (10 - a) liters
Now the equation will be,
Amount of solution (1) × 20% + Amount of solution (2) × 60% = Amount of final solution × 40%
[tex]a\times \frac{20}{100}+(10-a)\times \frac{60}{100}=10\times \frac{40}{100}[/tex]
20a + 60(10 - a) = 400
20a + 600 - 60a = 400
600 - 40a = 400
40a = 600 - 400
a = [tex]\frac{200}{40}[/tex]
a = 5 liters
Therefore, Dr Khan will add 5 liters of acetic acid to get 40% acetic acid solution.
Solution:
Let the amount of 20% acetic acid, he added to get 10 liters of 40% solution = 'a' liters
Volume of 60% solution used will be = (10 - a) liters
Equation will be,
Amount of solution (1) × 20% + Amount of solution (2) × 60% = Amount of final solution × 40%
a*20/100+(10-a)*60/100=10*40/100
20a + 60(10 - a) = 400
20a + 600 - 60a = 400
600 - 40a = 400
40a = 600 - 400
a=200/40
a = 5 liters
Thus, Dr Khan need to create 5 liters of acetic acid to get 40% acetic acid solution.
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