Answer:
[tex]x=z-\sqrt{-y} , or, x^2=z^2-y^2\\y=z-\sqrt{-x}, or, y^2=z^2-x^2[/tex]
Step-by-step explanation:
I can't do much except put the Pythagorean theorem in terms of y or x.
All I did was isolate x or y by subtracting the, x or y variable from each side.
[tex]-(y^2)+x^2 +y^2=z^2-(x^2)\\-(y^2)+x^2 +y^2=z^2-(y^2)[/tex]
Which tuns it into:
[tex]x^2=z^2-y^2\\y^2=z^2-x^2[/tex]
And I isolated further by squaring each side, but squaring negative number is difficult and causes imaginary numbers so I just think it should stay as all of them to the power of two.
