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Which equation represents a circle with a center at (2,8) and a radius of 11?
(x – 3)2 + (y + 2)2 = 11
(x-2)2 + (y + 8y2 = 121
(x + 2)2 + (y - 3)2 = 11
(x + 3)2 + (y – 2y = 121

Respuesta :

Isa0811

Answer:

[tex](x-2)^2+(y-8)^2=121[/tex]

Step-by-step explanation:

This is because if you can see that the, x is being subtracted by 2, making the x-coordinate +2. and the y is being subtracted by 8, making the y coordinate +8.

(2, 8) = Coordinates

And the reason it has a radius of 11 is because the 121 on the other is the product of 11 times 11.

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