Answer:
Mass, m = 0.49 kg
Explanation:
It is given that,
A block of ice is sliding down a ramp of slope 45° to the horizontal. At the bottom of the ramp, the block strikes a wall with a force of 3.4 N.
We need to find the mass of the ice.
On a sloping surface, the force with which it strikes is given by :
[tex]F=mg\cos\theta\\\\m=\dfrac{F}{g\cos\theta}\\\\m=\dfrac{3.4}{9.8\times \cos(45)}\\\\m=0.49\ kg[/tex]
So, the mass of the ice block is 0.49 kg.
