Answer:
The Number of unique permutation is 6,615
Step-by-step explanation:
This particular permutation deals with words that have repeated letters.
Given word = "ONGOING"
the formula for the permutation is
[tex]= \frac{n!}{mA! mB!.....mZ!}[/tex]
where n is the amount of letters in the word, and m
A
,
m
B
,
...
,
m
Z are the occurrences of repeated letters in the word. Each m equals the amount of times the letter appears in the word.
So in the word "ONGOING"
n= 7
mO= 2
mN= 2
mG=2
[tex]permutations = \frac{7!}{2!2!2!} \\\\permutations= \frac{7*6*5*4*3*2*1}{(2*1)*(2*1)*(2*1)}[/tex]
[tex]permutations= \frac{52920}{8} \\permutation = 6,615[/tex]
