Find the time required for an investment of 5000 dollars to grow to 6100 dollars at an interest rate of 7.5 percent per year, compounded quarterly.

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Answer:

The time (t) = 2.6 years

Step-by-step explanation:

To calculate the time for earning a compound interest, compounded on a certain amount of present value (PV), compounded periodically, the following formula is used:

[tex]FV=PV(1+\frac{i}{n} )^{n*t}[/tex]

where:

FV = future value = $6,100

PV = present value = $5,000

i = interest rate in decimal = 7.5% = 0.075

n = number of compounding periods per year = quarterly = 4 (4 quarters a year)

t = time of compounding in years = ???

Therefore the time is calculated thus:

[tex]6100=5000(1+\frac{0.075}{4} )^{4*t}[/tex]

[tex]6100=5000(1+0.01875 )^{4t}[/tex]

[tex]6100=5000(1.01875 )^{4t}[/tex]

Next, let us divide both sides of the equation by 5000

[tex]\frac{6100}{5000} = \frac{5000(1.01875)^{4t} }{5000}[/tex]

1.22 = [tex](1.01875)^{4t}[/tex]

Taking natural logarithm of both sides

㏑(1.22) = ㏑[tex](1.01875)^{4t}[/tex]

㏑(1.22) = 4t × ㏑(1.01875)

0.1989 = 4t × 0.01858

4t = [tex]\frac{0.1989}{0.01858} = 10.71[/tex]

∴ 4t = 10.71

t = 10.71 ÷ 4 = 2.6 years