An acorn falls from the branch of a tree to the ground 25 feet below. The distance, S, that the acorn is from the ground as it falls is represented by the equation S(t) = –16t2 + 25, where t is the number of seconds. For which interval of time is the acorn moving through the air?

Respuesta :

Answer:

0<t<5/4  or B

edge

The interval of time, the acorn moving through the air is t > 5/4.

What is a word problem?

A word problem is a verbal description of a problem situation. It consists of few sentences describing a 'real-life' scenario where a problem needs to be solved by way of a mathematical calculation.

For the given situation,

An acorn falls from the branch of a tree to the ground below = 25 feet

The equation is [tex]S(t) = -16t^2 + 25[/tex], where t is the number of seconds and

S is the distance.

At t=0,

⇒ [tex]S(0) = -16(0)^2 + 25[/tex]

⇒ [tex]S(0) = 25[/tex]

Initially, the acron is at 25 feet above the ground level. So t > 0, for the acron to fly on air.

The interval can be found as,

⇒ [tex]-16t^2 + 25 > 0[/tex]

⇒ [tex]-16t^2 > -25[/tex]

⇒ [tex]t^2 > \frac{25}{16}[/tex]

⇒ [tex]t > \sqrt{\frac{25}{16} }[/tex]

⇒ [tex]t > \frac{5}{4} or \frac{-5}{4}[/tex]

since t > 0, the interval is [tex]t > \frac{5}{4}[/tex]

Hence we can conclude that the interval of time, the acorn moving through the air is t > 5/4.

Learn more about word problems here

brainly.com/question/20594903

#SPJ2