Length and width of rectangle is 86 unit and 15 unit
Given that;
Perimeter of a rectangle = 202
Length of rectangle = 26 + 4[Width]
Find:
Dimensions of rectangle
Computation:
Assume;
Width of rectangle = a
So,
Length of rectangle = 4a + 26
Perimeter of a rectangle = 2[l + b]
202 = 2[(4a + 26) + a]
101 = 4a + 26 + a
5a + 26 = 101
5a = 75
a = 15
Width of rectangle = 15 unit
Length of rectangle = 4a + 26
Length of rectangle = 4(15) + 26
Length of rectangle = 60 + 26
Length of rectangle = 86 unit
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