Answer:
Option B.
Step-by-step explanation:
Let the radius of the snare drum = r
and radius of the model = R
Ratio of the dimensions of the snare drum and the model = 1 : 4
So, [tex]\frac{r}{R}=\frac{1}{4}[/tex]
Now as per question, dimensions of the snare drum is multiplied by a scale factor of [tex]\frac{1}{2}[/tex]
Radius of the snare drum = [tex]\frac{r}{2}[/tex]
Ratio of the radius of the snare drum and cylindrical model ,
[tex]\frac{\frac{r}{2}}{R} =\frac{1}{4}[/tex]
[tex]\frac{r}{2R}=\frac{1}{4}[/tex]
[tex]\frac{r}{R}=\frac{1}{2}[/tex]
Therefore, the cylinder with Sara's dimensions will be geometrically similar but the scale factor will be 1 : 2
Option B is the answer.