Respuesta :
Answer:
[tex]h \geq 2\frac{2}[3}[/tex]
Step-by-step explanation:
We solve the inequality similarly to how we would solve an equalitu.
[tex]6h - 5(h-1) \leq 7h - 11[/tex]
[tex]6h - 5h + 5 \leq 7h - 11[/tex]
[tex]h - 7h \leq -11 - 5/[/tex]
[tex]-6h \leq -16[/tex]
Multiplying everything by -1
[tex]6h \geq 16[/tex]
Simplifying by 2
[tex]3h \geq 8[/tex]
[tex]h \geq \frac{8}{3}[/tex]
8 divided by 3 is 2 with rest two. So as a improper fraction, the answer is:
[tex]h \geq 2\frac{2}[3}[/tex]
