Answer:
1.11 L
Explanation:
Given data
Step 1: Calculate the moles corresponding to 86.9 g of oxalic acid
The molar mass of oxalic acid is 90.03 g/mol.
[tex]86.9g \times \frac{1mol}{90.03g} = 0.965 mol[/tex]
Step 2: Calculate the volume of a 0.871 M solution that contains 0.965 moles of oxalic acid
The molarity is equal to the moles of solute (n) divided by the volume of the solution (V).
[tex]M = \frac{n}{V} \\V = \frac{n}{M} = \frac{0.965mol}{0.871 mol/L} =1.11 L[/tex]