Respuesta :

Answer:

1.11 L

Explanation:

Given data

  • Molarity of the oxalic acid solution (M): 0.871 M
  • Mass of oxalic acid (m): 86.9 g

Step 1: Calculate the moles corresponding to 86.9 g of oxalic acid

The molar mass of oxalic acid is 90.03 g/mol.

[tex]86.9g \times \frac{1mol}{90.03g} = 0.965 mol[/tex]

Step 2: Calculate the volume of a 0.871 M solution that contains 0.965 moles of oxalic acid

The molarity is equal to the moles of solute (n) divided by the volume of the solution (V).

[tex]M = \frac{n}{V} \\V = \frac{n}{M} = \frac{0.965mol}{0.871 mol/L} =1.11 L[/tex]