QueenlyLuv14 QueenlyLuv14

03-06-2020
Chemistry

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How much energy is required to heat 250 grams of water from 20.0°C to 80.0°C? The heat capacity of water is 4.186 J/g°C
Q=mc∆T

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yohanna69 yohanna69

03-06-2020

Answer:

62,790J

Explanation:

Q=mcT

= 250g*4.186J/gc*80-20

=250*4.186*60=62,790J

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