Respuesta :

Hrishii

Step-by-step explanation:

[tex]a) \\ log_{x}(15) \\ = log_{x}(3 \times 5) \\ = log_{x}3 + log_{x}5 \\ = 1.5 + 1.8 \\ = 3.3[/tex]

[tex]b) \\ log_{x}(2) \\ = log_{x}(\frac{10}{5}) \\ = log_{x}10 - log_{x}5 \\ = 3 - 1.8\\

= 1.2[/tex]

[tex]e) \\ log_{x}(150) \\ = log_{x}(3 \times 5\times 10) \\ = log_{x}3 + log_{x}5+ log_{x}10 \\ = 1.5 + 1.8 + 3\\ = 6.3[/tex]

[tex]f) \\ log_{x}(250) \\ = log_{x}( 5^2 \times 10) \\ = log_{x}5^2 + log_{x}10 \\

= 2log_{x}5 + log_{x}10 \\

= 2\times 1.8 + 3\\

= 3.6 + 3\\

= 6.6[/tex]

mirai123

Answer:

[tex]\log _x\left(6\right)[/tex]

[tex]$\frac{\text{log}(6)}{\text{log}(x)} =\frac{\text{log}(3)}{\text{log}x)}+\frac{\text{log}(3)}{\text{log}(x)}=\frac{1.5}{\text{log}(x)}+\frac{1.5}{\text{log}(x)}=\frac{3}{\log _{10}\left(x\right)}$[/tex]