Respuesta :

Answer:

Cost of the tires in 2008 = 23333 dollars

Step-by-step explanation:

Number of snow tires purchased are represented by,

T = [tex]\frac{500(t+20)}{(t+75)}[/tex]

Where t = duration from year 2000

Similarly, cost of the tires area represented by,

C = [tex]\frac{t+75}{1-.05t}[/tex]

Therefore, cost of T tires = C × T

= [tex]\frac{t+75}{1-.05t}[/tex] × [tex]\frac{500(t+20)}{(t+75)}[/tex]

= [tex]\frac{500(t+20)}{1-0.05t}[/tex]

Now cost of the tires in year 2008 (t = 8 years)

Total cost = [tex]\frac{500(8+20)}{(1-0.05\times 8)}[/tex]

                 = [tex]\frac{14000}{0.6}[/tex]            

                 = $23333.3

                 ≈ 23333 dollars

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