Respuesta :
Answer:
[tex] Ways = 3*5*7= 105[/tex]
And that's equivalent to:
[tex] Ways= (3C1) (5C1) (7C1) =3*5*7=105[/tex]
Where C represent the term combinatory defined as:
[tex] nCx = \frac{n!}{x! (n-x)!}[/tex]
And then the number of ways to select the three books are 105, and the best option would be:
b). 105
Step-by-step explanation:
For this case we can use the multplication principle of counting or sometimes called the product rule.
We have a total of 3 novels, 5 biographies and 7 self-help books. And we can find the number of ways that a person can select the three books with theis product:
[tex] Ways = 3*5*7= 105[/tex]
And that's equivalent to:
[tex] Ways= (3C1) (5C1) (7C1) =3*5*7=105[/tex]
Where C represent the term combinatory defined as:
[tex] nCx = \frac{n!}{x! (n-x)!}[/tex]
And then the number of ways to select the three books are 105, and the best option would be:
b). 105
We want to see in how many different ways a person can select one book from 3 novels, one book from 5 biographies and one book from 7 self-help books, the correct option is b: 105.
To get the numbe of different ways, the first thing we need to do is find the selections.
Here we have 3 selections:
- Novel selection.
- Biography selection
- Self-help selection.
Now we need to find the number of options for each of these selections, and just multiply the numbers of options.
we have:
- Novel selection: 3 options
- Biography selection: 5 options
- Self-help selection: 7 options
Number of different ways of selecting = 3*5*7 = 105
So the correct option is b.
If you want to learn more, you can read:
https://brainly.com/question/3349431