The solution to the system of equation is [tex]x=\frac{-5\pm \sqrt{13)}}{2}\[/tex]
Given the quadratic expression
x^2 = -5x - 3
Equate to zero
x^2+5x+3 = 0
Using the general formula will give:
[tex]x=\frac{-5\pm \sqrt{25-4(1)(3)}}{2}\\ x=\frac{-5\pm \sqrt{13)}}{2}\\[/tex]
Hence the solution to the system of equation is [tex]x=\frac{-5\pm \sqrt{13)}}{2}\[/tex]
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