Answer:
The transformed points of the triangle ABC are [tex]A' (x,y) = \left( \frac{1}{2}, \frac{1}{2}\right)[/tex], [tex]B'(x,y) = \left(\frac{9}{2}, \frac{1}{2} \right)[/tex], [tex]C'(x,y) = \left(\frac{1}{2}, \frac{9}{2}\right)[/tex]
Step-by-step explanation:
The new points after applying the scale factor are, respectively:
[tex]A' (x,y) = \frac{1}{2}\cdot (1,1)[/tex]
[tex]A' (x,y) = \left( \frac{1}{2}, \frac{1}{2}\right)[/tex]
[tex]B' (x,y) = \frac{1}{2}\cdot (9,1)[/tex]
[tex]B'(x,y) = \left(\frac{9}{2}, \frac{1}{2} \right)[/tex]
[tex]C'(x,y) = \frac{1}{2}\cdot (1,9)[/tex]
[tex]C'(x,y) = \left(\frac{1}{2}, \frac{9}{2}\right)[/tex]
