Answer:
Aloy has $55 initially
Benjamin has $95 initially
Step-by-step explanation:
In this question, given the order in which the money flowed in the question, we want to know how much each of the two had initially.
let what Aloys have be x and what Benjamin has be y.
Together, they had 150
x + y = 150 ••••••••(i)
Aloys mother gave him 40, new money is x + 40, Benjamin spent 10, new money is y-10
the new difference is 10
Thus;
(x + 40)-(y-10) = 10
x + 40 -y + 10 = 10
x+ 40 = y
substitute this into the first equation
x + 40 + x = 150
2x + 40 = 150
2x = 150-40
2x = 110
x = 110/2
x = $55
y = x + 40 = 55 + 40 = $95