blubabbls blubabbls
  • 02-06-2020
  • Mathematics
contestada

dy/dx of y=sin3xcos2x?

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TheLazyNobita
TheLazyNobita TheLazyNobita
  • 02-06-2020

Answer:

dy/dx = d/dx (sin3x.cos2x)

dy/dx = cos3x . 3 . -sin2x . 2 (Using chain rule)

dy/dx = -6cos3xsin2x

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