Answer:
320 Student Tickets
180 Adult Tickets
Step-by-step explanation:
You can solve this problem by using system of equations. First, we need to figure out our equations.
Equation 1: x as students and y as adults
[tex]x+y=500[/tex]
We get this equation because the total tickets sold was 500. The x represents the students sold to students, and the y represents the tickets sold to adults.
Equation 2:
[tex]3x+5y=1850[/tex]
We get this equation based on the prices. Each student ticket costs $3, and each adult ticket costs $5. The total amount earned was $1850.
Now that we have out equations, we can use system of equations to find our students and adults.
[tex]x+y=500[/tex]
[tex]3x+5y=1860[/tex]
Typically elimination is the easiest strategy because you are able to cross out variables.
[tex]3(x+y=500)[/tex]
[tex]3x+5y=1860[/tex]
Becomes:
[tex]3x+3y=1500[/tex]
[tex]3x+5y=1860[/tex]
We see that both equations now have 3x. We can cancel out 3x.
[tex]-2y=-360[/tex]
[tex]y=180[/tex]
Now that we know y=180, we can plug it back into one of our equations to find x.
[tex]x+180=500[/tex]
[tex]x=320[/tex]
320 student tickets and 180 adult tickets were sold.
