Answer:
Explanation:
Moment of inertia of each wheel = 1/2 m R²
m is mass and R is radius of wheel
= .5 x 15.5 x .175²
= .2373 kg m²
moment of inertia of tyre
1/2 m ( r₁² + r₂² )
= 1/2 x 1.9 x ( .315² + .19²)
= 1/2 x 1.9 x ( .099+ .036)
= .12825 kg m²
moment of inertia of tread
= 1/2 m r²
= .5 x 12 x .335²
= .67335 kg m²
moment of inertia of axle
= 1/2 m r ²
= .5 x 14.5 x .0195²
= .00275
moment of inertia of drive shaft
= 1/2 x 32.5 x .029²
= .0137 kg m ²
Total moment of inertia of one tyre
= 1.05535 kg m²
total moment of inertia of two rear wheels
= 2.1107 kg m²
95 % of torque
= .95 x 180
= 171 Nm
angular acceleration
= torque / moment of inertia
= 171 / 2.1107
= 81.01 radian /s²