Answer:
x=-4.73 and -1.26
Step-by-step explanation:
We need to solve the given equation for x.
[tex](x + 3)^2 - 3 =0[/tex]
Solving the above equation using formula (a+b)² =a²+2ab+b²
[tex](x + 3)^2 - 3 =0\\\\x^2+9+6x-3=0\\\\x^2+6x+6=0[/tex]
It is a quadratic equation.
[tex]x=\dfrac{-b\pm \sqrt{b^2-4ac} }{2a}[/tex]
We have, a = 1, b = 6 and c = 6
[tex]x=\dfrac{-6\pm \sqrt{(6)^2-4\times 1\times 6} }{2\times 1}\\\\x=\dfrac{-6+\sqrt{(6)^{2}-4\times1\times6}}{2\times1},\dfrac{-6-\sqrt{(6)^{2}-4\times1\times6}}{2\times1}\\\\x=-1.267, -4.73[/tex]
So, the values of x are -4.73 and -1.26
