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Antoine stands on a balcony and throws a ball to his dog, who is at ground level. The balls height (in meters above ground), x seconds after Antoine threw it, is modeled by: h(x) = 2x^2+4x+16
What is the height of the ball at the time it is thrown?

Respuesta :

Answer:

16 meters

Step-by-step explanation:

when the ball is thrown, the initial time is 0 seconds.  Therefore, x =0.  

h(0) = 2(0)^2 +4(0) + 16

h(0) = 16

the height of the ball at the time it is thrown is 16 meters.

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