Answer:
300mL
Explanation:
To obtain the volume of water added, let us calculate the volume of the diluted solution.
Data obtained from the question include:
Molarity of stock solution (M1) = 0.15mol/L
Volume of stock solution (V1) = 600mL
Molarity of diluted solution (M2) = 0.1mol/L
Volume of diluted solution (V2) =..?
The volume of the diluted solution can be obtained as follow:
M1V1 = M2V2
0.15 x 600 = 0.1 x V2
Divide both side by 0.1
V2 = 0.15 x 600 / 0.1
V2 = 900mL.
Therefore the volume of the diluted solution is 900mL.
Finally, we can obtain the volume of the water added by calculating the difference in the volume of the diluted solution and that of the stock solution. This is illustrated below:
Volume of stock solution (V1) = 600mL
Volume of diluted solution (V2) = 900mL
Volume of water added =...?
Volume of water added = V2 – V1
Volume of water added = 900 – 600
Volume of water added = 300mL
Therefore, the volume of water added is 300mL
