Respuesta :

Answer:

C) x = −5 and x = 1

Step-by-step explanation:

I took the test and I got it right

The solutions to the quadratic equation [tex]4(x + 2)^2 = 36[/tex] are as x = -5 and x = 1.

What is a solution for a quadratic equation?

Suppose that we've a function y = f(x) such that f(x) is quadratic.

When y = 0, then the values of x for which f(x) = 0 is called solution of quadratic equation f(x) = 0

This solution gives values of x, and when we plot x and f(x), we'd see that the graph intersects the x-axis at its solution points.

We have the given quadratic equation

[tex]4(x + 2)^2 = 36[/tex]

solving for x

[tex]4(x + 2)^2 = 36\\\\(x + 2)^2 = 36/4\\\\(x + 2)^2 = 9\\\\(x + 2)^2 = 3^2\\\\(x + 2) = 3\\\\x = 1\\or \\\\x + 2 = -3\\\\x = -5[/tex]

Learn more about quadratic equations;

brainly.com/question/13197897

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