Respuesta :

Answer:

1

Step-by-step explanation:

[tex]\frac{2^3}{2^3}\\\mathrm{Apply\:exponent\:rule}:\quad \frac{x^a}{x^b}=x^{a-b}\\=2^{3-3}\\2^{3-3}=1\\2^{3-3}\\\mathrm{Subtract\:the\:numbers:}\:3-3=0\\=2^0\\\mathrm{Apply\:rule}\:a^0=1,\:a\ne \:0\\=1[/tex]