Answer:
Rounded to the nearest tenth the solutions to the equation are:
x = -1.7 and x = -6.3
Step-by-step explanation:
Since this is a quadratic equation of the form:
[tex]ax^2+bx+c=0[/tex]
Use the quadratic formula, which tells you that the solutions would be given by:
[tex]x=\frac{-b+-\sqrt{b^2-4ac} }{2a}[/tex]
So in our case, the quadratic formula gives:
[tex]x=\frac{-b+-\sqrt{b^2-4ac} }{2a}\\x=\frac{-16+-\sqrt{16^2-4(2)(21)} }{2*2}\\x=\frac{-16+-\sqrt{88} }{4}[/tex]
which gives us two real solutions:
x = - 1.654792
x = -6.345207
Which rounded to the nearest tenth give:
x = -1.7 and x = -6.3
